50x^2=20x

Solution for 50x^2=20x equation:

50x^2=20x

We move all terms to the left:

50x^2-(20x)=0

a = 50; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·50·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*50}=\frac{0}{100}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*50}=\frac{40}{100}
=2/5
$